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derivative of 2x-3
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d
dx
(
2
x
−
3
)
=
2
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d
dx
(
2
x
−
3
)
=
2
steps
d
dx
(
2
x
−
3
)
Apply
the
Sum
/
Difference
Rule
:
(
f
±
g
)
′
=
f
′
±
g
′
=
d
dx
(
2
x
)
−
d
dx
(
3
)
show steps
d
dx
(
2
x
)
=
2
show steps
d
dx
(
3
)
=
0
=
2
−
0
Simplify
=
2
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