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partial derivative of 2xz
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∂
∂
x
(
2
xz
)
=
2
z
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∂
∂
x
(
2
xz
)
=
2
z
steps
∂
∂
x
(
2
xz
)
Treat
z
as
a
constant
Take
the
constant
out
:
(
a
·
f
)
′
=
a
·
f
′
=
2
z
∂
∂
x
(
x
)
Apply
the
common
derivative
:
∂
∂
x
(
x
)
=
1
=
2
z
·
1
Simplify
=
2
z
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