Partial Derivatives > partial derivative of 200+20sqrt(0.1x+10)-12\sqrt[3]{y}
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∂∂x (200+20√0.1x+10−123√y)=1√0.1x+10 
 
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∂ ∂ x (200+20√0.1x+10−123√y)=1√0.1x+10 
  • steps
    • ∂ ∂ x (200+20√0.1x+10−123√y)
  • Treat y as a constant
  • Apply the Sum/Difference Rule:    (f±g)′=f ′±g′
    =∂ ∂ x (200)+∂ ∂ x (20√0.1x+10)−∂ ∂ x (123√y)
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    ∂ ∂ x (200)=0
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    ∂ ∂ x (20√0.1x+10)=1√0.1x+10 
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    ∂ ∂ x (123√y)=0
    =0+1√0.1x+10 −0
  • Simplify
    =1√0.1x+10 

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