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partial derivative of 3ln(2x+y)
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∂
∂
x
(
3
ln
(
2
x
+
y
)
)
=
6
2
x
+
y
Show Steps
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∂
∂
x
(
3
ln
(
2
x
+
y
)
)
=
6
2
x
+
y
steps
∂
∂
x
(
3
ln
(
2
x
+
y
)
)
Treat
y
as
a
constant
Take
the
constant
out
:
(
a
·
f
)
′
=
a
·
f
′
=
3
∂
∂
x
(
ln
(
2
x
+
y
)
)
show steps
Apply
the
chain
rule
:
1
2
x
+
y
∂
∂
x
(
2
x
+
y
)
=
1
2
x
+
y
∂
∂
x
(
2
x
+
y
)
show steps
∂
∂
x
(
2
x
+
y
)
=
2
=
3
·
1
2
x
+
y
·
2
show steps
Simplify
3
·
1
2
x
+
y
·
2
:
6
2
x
+
y
=
6
2
x
+
y
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