ddx (ex+y)=ex+y(1+dydx )
 
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ddx (ex+y)=ex+y(1+dydx )
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  • ddx (ex+y)

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    Apply the chain rule:    ex+yddx (x+y)
    =ex+yddx (x+y)

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    ddx (x+y)=1+dydx 
    =ex+y(1+dydx )

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