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partial derivative of x^2y+2y^2-6x+3y-4
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∂
∂
x
(
x
2
y
+
2
y
2
−
6
x
+
3
y
−
4
)
=
2
xy
−
6
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∂
∂
x
(
x
2
y
+
2
y
2
−
6
x
+
3
y
−
4
)
=
2
xy
−
6
steps
∂
∂
x
(
x
2
y
+
2
y
2
−
6
x
+
3
y
−
4
)
Treat
y
as
a
constant
Apply
the
Sum
/
Difference
Rule
:
(
f
±
g
)
′
=
f
′
±
g
′
=
∂
∂
x
(
x
2
y
)
+
∂
∂
x
(
2
y
2
)
−
∂
∂
x
(
6
x
)
+
∂
∂
x
(
3
y
)
−
∂
∂
x
(
4
)
show steps
∂
∂
x
(
x
2
y
)
=
2
yx
show steps
∂
∂
x
(
2
y
2
)
=
0
show steps
∂
∂
x
(
6
x
)
=
6
show steps
∂
∂
x
(
3
y
)
=
0
show steps
∂
∂
x
(
4
)
=
0
=
2
yx
+
0
−
6
+
0
−
0
Simplify
=
2
xy
−
6
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