x (ln(x+x2+y2))=1x2+y2 
 
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x (ln(x+x2+y2))=1x2+y2 
  • steps
  • x (ln(x+x2+y2))

  • Treat y as a constant

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    Apply the chain rule:    1x+x2+y2  x (x+x2+y2)
    =1x+x2+y2  x (x+x2+y2)

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    x (x+x2+y2)=1+xx2+y2 
    =1x+x2+y2 (1+xx2+y2 )

  • show steps
    Simplify 1x+x2+y2 (1+xx2+y2 ):    1x2+y2 
    =1x2+y2 

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