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derivative of ax^2+bx+c
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d
dx
(
ax
2
+
bx
+
c
)
=
2
ax
+
b
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d
dx
(
ax
2
+
bx
+
c
)
=
2
ax
+
b
steps
d
dx
(
ax
2
+
bx
+
c
)
Apply
the
Sum
/
Difference
Rule
:
(
f
±
g
)
′
=
f
′
±
g
′
=
d
dx
(
ax
2
)
+
d
dx
(
bx
)
+
dc
dx
show steps
d
dx
(
ax
2
)
=
2
ax
show steps
d
dx
(
bx
)
=
b
show steps
dc
dx
=
0
=
2
ax
+
b
+
0
Simplify
=
2
ax
+
b
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