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partial derivative of 2x^2+4xy+3y^2^{1/2}
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∂
∂
x
(
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
)
=
2
(
x
+
y
)
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
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∂
∂
x
(
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
)
=
2
(
x
+
y
)
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
steps
∂
∂
x
(
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
)
Treat
y
as
a
constant
show steps
Apply
the
chain
rule
:
1
2
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
∂
∂
x
(
2
x
2
+
4
xy
+
3
y
2
)
=
1
2
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
∂
∂
x
(
2
x
2
+
4
xy
+
3
y
2
)
show steps
∂
∂
x
(
2
x
2
+
4
xy
+
3
y
2
)
=
4
x
+
4
y
=
1
2
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
(
4
x
+
4
y
)
show steps
Simplify
1
2
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
(
4
x
+
4
y
)
:
2
(
x
+
y
)
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
=
2
(
x
+
y
)
(
2
x
2
+
4
xy
+
3
y
2
)
1
2
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