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partial derivative of x^2y+e^{xy}
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∂
∂
x
(
x
2
y
+
e
xy
)
=
2
yx
+
e
xy
y
Show Steps
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∂
∂
x
(
x
2
y
+
e
xy
)
=
2
yx
+
e
xy
y
steps
∂
∂
x
(
x
2
y
+
e
xy
)
Treat
y
as
a
constant
Apply
the
Sum
/
Difference
Rule
:
(
f
±
g
)
′
=
f
′
±
g
′
=
∂
∂
x
(
x
2
y
)
+
∂
∂
x
(
e
xy
)
show steps
∂
∂
x
(
x
2
y
)
=
2
yx
show steps
∂
∂
x
(
e
xy
)
=
e
xy
y
=
2
yx
+
e
xy
y
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