ddx (x+1x )=1x2 
 
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ddx (x+1x )=1x2 
  • steps
  • ddx (x+1x )

  • Apply the Quotient Rule:    (fg )=f ·gg·fg2 
    =ddx (x+1)xdxdx (x+1)x2 

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    ddx (x+1)=1
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    dxdx =1
    =1· x1·(x+1)x2 

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    Simplify 1· x1·(x+1)x2 :    1x2 
    =1x2 

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