Partial Derivatives > partial derivative of 1/(t^2-x^2)
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∂∂x (1t2−x2 )=2x(t2−x2)2 
 
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∂ ∂ x (1t2−x2 )=2x(t2−x2)2 
  • steps
    • ∂ ∂ x (1t2−x2 )
  • Treat t as a constant
  • Apply exponent rule:    1a =a−1
    =∂ ∂ x ((t2−x2)−1)
  • show steps
    Apply the chain rule:    −1(t2−x2)2 ∂ ∂ x (t2−x2)
    =−1(t2−x2)2 ∂ ∂ x (t2−x2)
  • show steps
    ∂ ∂ x (t2−x2)=−2x
    =−1(t2−x2)2 (−2x)
  • show steps
    Simplify −1(t2−x2)2 (−2x):    2x(t2−x2)2 
    =2x(t2−x2)2 

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