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partial derivative of e^xxy+e^xy^2+e^xy
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∂
∂
y
(
e
x
xy
+
e
x
y
2
+
e
x
y
)
=
xe
x
+
2
e
x
y
+
e
x
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∂
∂
y
(
e
x
xy
+
e
x
y
2
+
e
x
y
)
=
xe
x
+
2
e
x
y
+
e
x
steps
∂
∂
y
(
e
x
xy
+
e
x
y
2
+
e
x
y
)
Treat
x
as
a
constant
Apply
the
Sum
/
Difference
Rule
:
(
f
±
g
)
′
=
f
′
±
g
′
=
∂
∂
y
(
e
x
xy
)
+
∂
∂
y
(
e
x
y
2
)
+
∂
∂
y
(
e
x
y
)
show steps
∂
∂
y
(
e
x
xy
)
=
xe
x
show steps
∂
∂
y
(
e
x
y
2
)
=
2
e
x
y
show steps
∂
∂
y
(
e
x
y
)
=
e
x
=
xe
x
+
2
e
x
y
+
e
x
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