Partial Derivatives > partial derivative of xyz-tan(x+y+z)
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∂∂x (xyz−tan(x+y+z))=yz−sec2(x+y+z)
 
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∂ ∂ x (xyz−tan(x+y+z))=yz−sec2(x+y+z)
  • steps
    • ∂ ∂ x (xyz−tan(x+y+z))
  • Treat y, z as constants
  • Apply the Sum/Difference Rule:    (f±g)′=f ′±g′
    =∂ ∂ x (xyz)−∂ ∂ x (tan(x+y+z))
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    ∂ ∂ x (xyz)=yz
    show steps
    ∂ ∂ x (tan(x+y+z))=sec2(x+y+z)
    =yz−sec2(x+y+z)

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