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derivative of x^2y^3
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d
dx
(
x
2
y
3
)
=
2
xy
3
+
3
y
2
dy
dx
x
2
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d
dx
(
x
2
y
3
)
=
2
xy
3
+
3
y
2
dy
dx
x
2
steps
d
dx
(
x
2
y
3
)
Apply
the
Product
Rule
:
(
f
·
g
)
′
=
f
′
·
g
+
f
·
g
′
f
=
x
2
,
g
=
y
3
=
d
dx
(
x
2
)
y
3
+
d
dx
(
y
3
)
x
2
show steps
d
dx
(
x
2
)
=
2
x
show steps
d
dx
(
y
3
)
=
3
y
2
dy
dx
=
2
xy
3
+
3
y
2
dy
dx
x
2
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